1kg liquid water
100°C
1 atm
One kilogram of liquid water at 100°C is vaporized to steam at 100°C in a piston. (Equilibrium can be assumed). What procedure is needed to determine how much heat would be required and how much work is done in this process? If Q does not equal W, what accounts for the difference?
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From the problem statement, we know the mass, temperature, and state of the water. We see that the change in state occurs at a temperature that is water's normal boiling point. Because the temperature is at the normal boiling point, the temperature is 1 atm. |
Lowers | Rises?