Note that by contrast with the integral statement of Gauss' law,
(1.3.1), the surface integral symbols on the right do not have circles.
This means that the integrations are over open surfaces, having edges
denoted by the contour C. Such a surface S enclosed by a contour C is
shown in Fig. 1.4.1. In words, Ampère's integral law as given by (1)
requires that the line
integral (circulation) of the magnetic field
intensity H around a closed contour is equal to the net current
passing through the surface spanning the contour plus the time rate of
change of the net displacement flux density o E through the
surface (the displacement current).
A constant current in the z direction within the circular
cylindrical region of radius R, shown in Fig. 1.4.2, extends from -
infinity to + infinity along the z axis and is represented by the
density
where Jo and R are given constants. The associated magnetic field
intensity has only an azimuthal component.
Figure 1.4.2. Axially symmetric current
distribution and associated radial distribution of azimuthal magnetic
field intensity. Contour C is used to determine azimuthal H,
while C' is used to show that the z-directed field must be
uniform.
To see that there can be no r component of this field, observe that
rotation of the source around the radial axis, as shown in Fig. 1.4.2,
reverses the source (the current is then in the -z direction) and
hence must reverse the field. But an r component of the field does
not reverse under such a rotation and hence must be zero. The
H and Hz components are not ruled out by this argument.
However, if they
exist, they must not depend upon the and z coordinates, because
rotation of the source around the z axis and translation of the source
along the z axis does not change the source and hence does not change
the field.
The current is independent of time and so we assume that the
fields are as well. Hence, the last term in (1), the displacement
current, is zero. The law is then used with S, a surface having its
enclosing contour C at the arbitrary radius r, as shown in Fig. 1.4.2.
Then the area and line elements are
and the right-hand side of (1) becomes
Integration on the left-hand side amounts to a multiplication of the
independent H by the length of C.
These last two expressions are used to evaluate (1) and obtain
Thus, the azimuthal magnetic field intensity has the radial
distribution shown in Fig. 1.4.2.
The z component of H is, at most, uniform. This can be seen by
applying the integral law to the contour C', also shown in
Fig. 1.4.2. Integration on the top and bottom legs gives zero
because Hr = 0. Thus,
to make the contributions due to Hz on the vertical legs cancel, it is
necessary that Hz be independent of radius. Such a uniform field must
be caused by sources at infinity and is therefore set equal to zero
if such sources are not postulated in the statement of the problem.