The Vector Potential and the Vector Poisson Equation | |||||||||
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8.1.1 | A solenoid has radius a, length d, and turns N, as shown in Fig.
8.2.3. The length d is much greater than a, so it can be
regarded as being infinite. It is driven by a current i.
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8.1.2* | A two-dimensional magnetic quadrupole is composed of four line currents of magnitudes i, two in the positive z direction at x = 0, y = d/2 and two in the negative z direction at x = d/2, y = 0. (With the line charges representing line currents, the cross-section is the same as shown in Fig. P4.4.3.) Show that in the limit where r d, Az = - (o id2/4 )(r-2) cos 2. (Note that distances must be approximated accurately to order d2.) | ||||||||
8.1.3 | A two-dimensional coil, shown in cross-section in Fig. P8.1.3, is
composed of N turns of length l in the z direction that is much
greater than the width w or spacing d. The thickness of the windings
in the y direction is much less than w and d. Each turn carries the
current i. Determine A.
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The Biot-Savart Superposition Integral | |||||||||
8.2.1* | The washer-shaped coil shown in Fig. P8.2.1 has a thickness
that is much less than the inner radius b and outer
radius a. It supports a current density J = Jo i.
Show that along the z axis,
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8.2.2* | A coil is wound so that the wire forms a spherical shell of
radius R with the wire essentially running in the direction.
With the wire driven by a current source, the resulting current
distribution is a surface current at r = R having the density
K = Ko sin i, where Ko is a given constant.
There are no other currents. Show that at the center of the
coil, H = (2Ko/3)iz.
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8.2.3 | In the configuration of Prob. 8.2.2, the surface current density is uniformly distributed, so that K = Ko i, where Ko is again a constant. Find H at the center of the coil. | ||||||||
8.2.4 | Within a spherical region of radius R, the current density is
J = Jo i, where Jo is a given constant. Outside
this region is free space and no other sources of H. Determine
H at the origin.
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8.2.5* | A current i circulates around a loop having the shape of an
equilateral triangle having sides of length d, as shown in Fig.
P8.2.5. The loop is in the z = 0 plane. Show that along the z
axis,
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8.2.6 | For the two-dimensional coil of Prob. 8.1.3, use the Biot-Savart superposition integral to find H along the x axis. | ||||||||
8.2.7* | Show that A induced at point P by the current stick of Figs.
8.2.5 and 8.2.6 is
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The Scalar Magnetic Potential | |||||||||
8.3.1 | Evaluate the H field on the axis of a circular loop of radius R
carrying a current i. Show that your result is consistent with the
result of Example 8.3.2 at distances from the loop much greater than
R.
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8.3.2 | Determine for two infinitely long parallel thin wires carrying currents i in opposite directions parallel to the z axis of a Cartesian coordinate system and located along x = a. Show that the lines = const in the x - y plane are circles. | ||||||||
8.3.3 | Find the scalar potential on the axis of a stack of circular
loops (a coil) of N turns and length l using 8.3.12 for an
individual turn, integrating over all the turns. Find H on the
axis.
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Magnetoquasistatic Fields in the Presence of Perfect Conductors | |||||||||
8.4.1* | A current loop of radius R is at the center of a conducting
spherical shell having radius b. Assume that R b and
that i(t) is so rapidly varying that the shell can be taken as
perfectly conducting. Show that in spherical coordinates, where R
r < b
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8.4.2 | The two-dimensional magnetic dipole of Example 8.1.2 is at the center of a conducting shell having radius a d. The current i(t) is so rapidly varying that the shell can be regarded as perfectly conducting. What are and H in the region d r < a? | ||||||||
8.4.3* | The cross-section of a two-dimensional system is shown in Fig.
P8.4.3. A magnetic flux per unit length so Ho is trapped
between perfectly conducting plane parallel plates that extend to
infinity to the left and right. At the origin on the lower plate is a
perfectly conducting half-cylinder of radius R.
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8.4.4 | In a three-dimensional version of that shown in Fig. P8.4.3, a perfectly conducting hemispherical bump of radius s R is attached to the lower of two perfectly conducting plane parallel plates. The hemisphere is centered at the origin of a spherical coordinate system such as in Fig. P8.4.3, with . The magnetic field intensity is uniform far from the hemisphere. Determine and H. | ||||||||
8.4.5* | Running from z = - to z = + at (x, y) = (0, -h) is
a wire. The wire is parallel to a perfectly conducting plane at y = 0.
When t = 0, a current step i = I u-1(t) is applied in the +z
direction to the wire.
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8.4.6 | The cross-section of a system that extends to infinity in the
z directions is shown in Fig. P8.4.6. Surrounded by free space,
a sheet of current has the surface current density Ko iz
uniformly distributed between x = b and x = a. The plane x = 0
is perfectly conducting.
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Piece-Wise Magnetic Fields | |||||||||
8.5.1* | The cross-section of a cylindrical winding is shown in Fig.
P8.5.1. As projected onto the y = 0 plane, the number of turns per unit
length is constant and equal to N/2R. The cylinder can be modeled as
infinitely long in the axial direction.
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8.5.2 | The cross-section of a rotor, coaxial with a perfectly conducting
"magnetic shield," is shown in Fig. P8.5.2. Windings consisting of N
turns per unit peripheral length are distributed uniformly at r = b so
that at a given instant in time, the surface current distribution is as
shown. At r = a, there is the inner surface of a perfect conductor. The
system is very long in the z direction.
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Vector Potential | |||||||||
8.6.1* | In Example 1.4.1, the magnetic field intensity is determined to
be that given by (1.4.7). Define Az to be zero at the origin.
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8.6.2 | For the configuration of Prob. 1.4.2, define Az as being zero
at the origin.
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8.6.3* | In cylindrical coordinates, o H = o [Hr(r, z)ir + Hz(r,
z)iz].
That is, the magnetic flux density is axially symmetric and does not
have a component.
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8.6.4* | For the inductive attenuator considered in Example 8.6.3 and
Demonstration 8.6.2:
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8.6.5 | Perfectly conducting electrodes are composed of sheets bent into
the shape of 's, as shown in Fig. P8.6.5. The length of the
system in the z direction is very large compared to the length 2a or
height d, so the fields can be regarded as two dimensional. The
insulating gaps have a width that is small compared to all
dimensions. Passing through these gaps is a magnetic flux (per unit
length in the z direction) (t). One method of solution
is suggested by Example 6.6.3.
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8.6.6* | The wires comprising the winding shown in cross-section by Fig.
P8.6.6 carry current in the -z direction over the range 0 < x < a and
return this current over the range -a < x < 0. These windings extend
uniformly over the range 0 < y < b. Thus, the current density in the
region of interest is J = - ino sin ( x/a)iz, where i
is the current carried by each wire and |no sin ( x/a)| is the
number of turns per unit area. This region is surrounded by perfectly
conducting walls at y = 0 and y = b and at x = -a and x = a.
The length l in the z direction is much greater than either a or b.
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8.6.7 | In the configuration of Prob. 8.6.6, the rectangular region is
uniformly filled with wires that all carry their current in the z
direction. There are no of these wires per unit area. The
current carried by each wire is returned in the perfectly conducting
walls.
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8.6.8 | In the configuration of Prob. 8.6.6, the turns are uniformly
distributed. Thus, no is a constant representing the number of
wires per unit area carrying current in the -z direction in the region
0 < x. Assume that the wire carrying current in the -z direction at the
location (x, y) returns the current at (-x, y).
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