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x + y 2 = z i 2

- 2 ln | x - 2 | + 3 ln | x - 3 | + C

y = k e x 2 2 - 1

d r d t = 1 π

[ - 1 / 3 , 0 ] [ 1 / 3 , + &infty; ]

cos x 2 sin x

A = 0 1 ln ( x + 1 ) x 2 + 2 x + 2 x + 1 d x

1 2 0 π / 2 sin 2 3 θ d θ = π 12