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submodule

submodule generated by list

Syntax 
submodule(L: LIST of MODULEELEM): MODULE
submodule(F: MODULE, L: LIST of MODULEELEM): MODULE

Description
The first form returns the ideal generated by L . The second is the same as the first but works also if L = [] .

This function is not friendly if you write the input by hand: we suggest SubmoduleCols, SubmoduleRows for creating a module from the rows or columns of a matrix.

NOTE: the second argument is a LIST of MODULEELEM, not a LIST of LISTS of RINGELEM.

Example 
/**/  Use R ::= QQ[x,y,z];
/**/  R3 := NewFreeModule(R, 3);
/**/  L := [ModuleElem(R3, [x,y,z]), ModuleElem(R3, [x-1,0,z])];
/**/  M := submodule(R3, L); -- equivalent to
/**/  M := submodule(L);     -- (L not empty)
/**/  gens(M);
[[x, y, z], [x -1, 0, z]]

See Also