13.021 Marine Hydrodynamics, Fall 2003

Lecture 2

Copyright © 2003 MIT - Department of Ocean Engineering, All rights reserved.

13.021 - Marine Hydrodynamics
Lecture 2

Chapter 1 - Basic Equations

1.1 - Description of a Flow.

Flows are often defined either by an Eulerian description or a Lagrangian description.

Useful terms for flow description

Some Eulerian Quantities of Interest

Concept of Continuous Flow

For a fluid flow to be continuous, we require that the velocity $ \vec{v}(\vec{x},t) $ be a finite and continuous function of $ \vec{x} $ and t. i.e. $ \nabla \cdot \vec{v} $ and $ \frac{\partial \vec{v} }{
\partial t}$ are finite but not necessarily continuous. Since $ \nabla \cdot \vec{v} $ and $ \frac{\partial \vec{v} }{
\partial t}$ < $ \infty$, there is no infinite acceleration, which is physically consistent.

Consequences of Continuous Flow

Given: Two particles with initial position $ \vec{x} $ and $ \vec{x}+\delta\vec{x} $, initial time t and the fluid velocity v.

Proof:
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Where $ \vec{v}\delta t $ is the distance travelled by the particle. The difference in position between the two particles is:

$\displaystyle \left[\vec{x}(t)+\delta\vec{x}(t)\right]+\left(\vec{v}+\delta\vec...
...\vec{v}\right)\delta 
 t-\vec{x}(t)-\vec{v}\delta t = \delta\vec{x}(t+\delta t)$ (1)

$\displaystyle \Rightarrow   \delta\vec{x}(t+\delta 
 t) = \delta\vec{x}(t)+\delta\vec{x}(t)\cdot\nabla\vec{v}\delta t \propto \delta\vec{x}(t)$    

Therefore $ \delta\vec{x}(t+\delta t) \propto \delta \vec{x}(t) $ since $ \nabla \vec{v} $ is finite due to the continuous flow assumption. Therefore if $ \delta \vec{x}(t) \rightarrow 0 $ , then $ \delta \vec{x}(t+\delta t) \rightarrow 0$. In fact, for any time period T,

$\displaystyle \delta \vec{x}(t+T) \propto \delta \vec{x}(t)+\int_{t}^{t+T}\delta\vec{x}\cdot\nabla
 \vec{v}dt \propto \delta\vec{x},$    

and $ \delta \vec{x}(t+T) \rightarrow 0 $ as $ \delta \vec{x}(t) \rightarrow 0 $ , therefore the particles will never be an infinite distance apart. Thus the flow is continuous and two particles that are neighbors will always be neighbors.

Material/Substantial Derivative: D/Dt

A material derivative is the time derivative - rate of change - of a property `following a fluid particle P'. The material derivative is a Lagrangian concept but we will work in an Eulerian reference frame.

Consider an Eulerian quantity $ f(\vec{x},t) $. Taking the Lagrangian time derivative of an Eulerian quantity gives the material derivative. The Lagrangian time derivative is:

\begin{displaymath}\begin{split}
 \frac{Df(\vec{x},t)}{Dt} & =\frac{df}{dt} =\le...
...vec{v}\delta t,t+\delta t)-f(\vec{x},t)}{\delta
 t} \end{split}\end{displaymath}    

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P is moving at an Eulerian velocity $ \vec{v} =
\frac{\delta\vec{x}}{\delta t} $. Performing a 3D Taylor series on f gives:

$\displaystyle f( \vec{x},t+\delta t) = f(\vec{x},t)+\delta t\frac{\partial f(\vec{x},t)}{\partial 
 t}+\delta \vec{x}\cdot\nabla f(\vec{x},t)+O(\delta^{2})$   (higher order terms)    

Therefore the substantial derivative is:

$\displaystyle \frac{Df}{Dt} =\frac{\partial f}{\partial t} +\vec{v}\cdot\nabla f$    

With the generalized notation:

$\displaystyle \underset{\mbox{Lagrangian}}{\underbrace{\frac{D}{Dt} }} \equiv
 ...
...mbox{Eulerian}}{\underbrace{\frac{\partial }{\partial t} +\vec{v}\cdot\nabla }}$    

Example: Lagrangian acceleration of a particle. Consider the Eulerian velocity $ \vec{v}(\vec{x},t) $. Then the Lagrangian acceleration is:

$\displaystyle \underset{\mbox{ \begin{tabular}{c} Lagragian  
 acceleration \...
...lar}{c} Convective  
 acceleration \end{tabular}}}{\vec{v}\cdot\nabla\vec{v}}$    

Difference between Lagrangian time derivative and Eulerian time derivative

Example: Consider an Eulerian quantity, temperature, in a room at points A and B where the temperature is different at each point.

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At point C, the temperature rate of change is $ \frac{\partial T}{\partial t} $ which is an Eulerian time derivative.

Example: Consider the same example as above: an Eulerian quantity, temperature, in a room at points A and B where the temperature varies with time.

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Following a particle from point A to B, the Lagrangian time derivative would need to include the temperature gradient as time and position changed: $ \frac{DT}{Dt}
=\frac{\partial T}{\partial t} +\vec{v}\cdot\nabla T $

Concept of a Steady Flow

Assume a steady flow where the flow is observed from a fixed position. This is like watching from a river bank, i.e. $ \frac{\partial }{\partial t} =0$ . Be careful not to confuse this with $ \frac{D}{Dt} $ which is more like following a twig in the water. Note that $ \frac{D}{Dt} =0$ does not mean steady since the flow could speed up at some points and slow down at others.

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Karl P Burr 2003-08-31