located at $(x_{0},y_{0}, z_{0})$ and oriented in the $+x$ direction.


\begin{displaymath}\phi = -\frac{\mu}{4\pi}\frac{(x-x_{0})}{r^{3}} \notag
\end{displaymath}  

where $r = \sqrt{(x-x_{0})^{2}+(y-y_{0})^{2}+(z-z_{0})^{2}}$.

Timothy S Choe
2003-03-15