a. Verify that the average distance per response dav = 5.1 miles, the average
speed per response Sav =
12.5 miles/hr, and the average time per response tav = 19.1 minutes.
b. Intuitively, explain why (dav/Sav) x (60
minutes/hr) = 24.48 minutes is greater than tav = 19.1 minutes.
c. If we compute a weighted average speed Swt, where the
weights sum to 1 and are proportional to the times driven at each speed, we find Swt
= 16.03 miles/hr. We find that (dav/Swt x 60 minutes/hr) = tav
= 19.1 minutes. Why is this a correct procedure?