Solution:
Solution:
1) p1 = Prob. that any particular ambulance is covered by an ambulance p1 = a/(1+a)
2) Prob. that x is covered by at least one ambulance is PN = 1 - P{x not covered by any ambulance}
PN = 1 - (1-p1)N = 1 - (1/[1+a])N
0
1
-a/2
1+a/2
a
x
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