Fast Discrete Fourier Transform (FFT)

Description

Computes the Discrete Fourier Transform (DFT) of an array with a fast algorithm, the “Fast Fourier Transform” (FFT).

Usage

fft(z, inverse = FALSE)
mvfft(z, inverse = FALSE)

Arguments

Value

When z is a vector, the value computed and returned by fft is the unnormalized univariate discrete Fourier transform of the sequence of values in z. Specifically, y <- fft(z) returns

y[h] = sum_{k=1}^n z[k]*exp(-2*pi*1i*(k-1)*(h-1)/n)

for h = 1, ..., n where n = length(y). If inverse is TRUE, exp(-2*pi...) is replaced with exp(2*pi...).

When z contains an array, fft computes and returns the multivariate (spatial) transform. If inverse is TRUE, the (unnormalized) inverse Fourier transform is returned, i.e., if y <- fft(z), then z is fft(y, inverse = TRUE) / length(y).

By contrast, mvfft takes a real or complex matrix as argument, and returns a similar shaped matrix, but with each column replaced by its discrete Fourier transform. This is useful for analyzing vector-valued series.

The FFT is fastest when the length of the series being transformed is highly composite (i.e., has many factors). If this is not the case, the transform may take a long time to compute and will use a large amount of memory.

Source

Uses C translation of Fortran code in Singleton (1979).

References

Becker, R. A., Chambers, J. M. and Wilks, A. R. (1988) The New S Language. Wadsworth & Brooks/Cole.

Singleton, R. C. (1979) Mixed Radix Fast Fourier Transforms, in Programs for Digital Signal Processing, IEEE Digital Signal Processing Committee eds. IEEE Press.

Cooley, James W., and Tukey, John W. (1965) An algorithm for the machine calculation of complex Fourier series, Math. Comput. 19(90), 297–301. https://dx.doi.org/10.1090/S0025-5718-1965-0178586-1

See Also

convolve, nextn.

Examples

x <- 1:4
fft(x)
fft(fft(x), inverse = TRUE)/length(x)

## Slow Discrete Fourier Transform (DFT) - e.g., for checking the formula
fft0 <- function(z, inverse=FALSE) {
  n <- length(z)
  if(n == 0) return(z)
  k <- 0:(n-1)
  ff <- (if(inverse) 1 else -1) * 2*pi * 1i * k/n
  vapply(1:n, function(h) sum(z * exp(ff*(h-1))), complex(1))
}

relD <- function(x,y) 2* abs(x - y) / abs(x + y)
n <- 2^8
z <- complex(n, rnorm(n), rnorm(n))
## relative differences in the order of 4*10^{-14} :
summary(relD(fft(z), fft0(z)))
summary(relD(fft(z, inverse=TRUE), fft0(z, inverse=TRUE)))