During the Fall semester thermodynamics lectures we used the *steady flow
energy equation* to relate the exhaust velocity of a rocket motor to the
conditions in the combustion chamber and the exit pressure

**Figure 5.1** Schematic of rocket
nozzle and combustion chamber

The steady flow energy equation

_{}

then with no heat transfer or shaft work

_{}

which can be written as

_{}

and manipulated to obtain

_{}
_{}

Then considering the relationship we derived for thrust

_{}
and assuming p_{e} = p_{o} =
0

then _{}

and _{}

so _{}

Thus the specific impulse can be directly related to the exhaust velocity leaving the rocket

_{}

We can now look at the role of specific impulse in setting the performance of a rocket. A large fraction (typically 90%) of the mass of a rocket is propellant, thus it is important to consider the change in mass of the vehicle as it accelerates.

**Figure 5.2** Schematic for application
of the momentum theorem.

There are several ways to do this through applying conservation of momentum. Here we will apply the momentum theorem differentially by considering a small mass, dm, expelled from the rocket during time dt.

The initial momentum of the mass in the control volume (the vehicle) is

m_{v}u

The final momentum of mass in the control volume (the vehicle and the mass expelled, dm) is

(m_{v }- dm)(u + du) + dm(u - u_{e})

= m_{v}u
+ m_{v} du - udm – dudm +udm
-u_{e}dm

The change in momentum during the interval dt is

= momentum_{final} – momentum_{initial}

= m_{v} du - u_{e}dm (since dudm is a
higher order term)

Now consider the forces acting on the system which is composed of the masses m (the rocket), and dm (the small amount of propellant expelled from the rocket during time dt):

_{}

Applying conservation of momentum, the resulting impulse, SFdt, must balance the change in momentum of the system.

_{}

then since _{} where
_{} = propellant
mass flow rate

we have

_{}

or for p_{e} = p_{o}

_{}
__The Rocket Equation__

The above can be integrated as a function of time to determine the velocity of the rocket.

If we set u_{e} = constant, and assume that at t=0, u=0, and neglect
drag, and set q = 0, then we arrive at

_{}

which can be integrated to give

_{}
whereis
the initial mass of the rocket

or

_{}

We can view this equation as being similar to the Breguet Range Equation for aircraft. It presents the overall dependence of the principal performance parameter for a rocket (velocity, u), on the efficiency of the propulsion system (Isp), and the structural design (ratio of total mass to structural mass – since the initial mass is the fuel mass plus the structural mass and the final mass. is only the structural mass).

Assuming the rate of fuel consumption is constant, the mass of the rocket varies over time as

where t_{b} is the time at which all of the
propellant is used. This expression can be substituted into the equation
for velocity and then integrated to find the height at the end of burnout:

_{}

which for a single stage sounding rocket with no drag and constant gravity yields

** **_{}

the final height of the rocket can then be determined by equating the kinetic energy of the vehicle at burnout with its change in potential energy between that point and the maximum height. This is left as an exercise for the reader.

GO! |

**Figure 5.3** The Saturn
V rocket stood 365 feet tall and had 5 stages. It produced over 7.5 million
pounds of thrust at liftoff (NASA, 1969).

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