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13.5
Dielectric Waveguides: Optical Fibers

Waves can be guided by dielectric rods or slabs and the fields of these waves occupy the space within and around these dielectric structures. Especially at optical wavelengths, dielectric fibers are commonly used to guide waves. In this section, we develop the properties of waves guided by a planar sheet of dielectric material. The waves that we find are typical of those found in integrated optical systems and in the more commonly used optical fibers of circular cross-section.

A planar version of a dielectric waveguide is pictured in Fig. 13.5.1. A dielectric of thickness 2d and permittivity _i is surrounded by a dielectric of permittivity < _i. The latter might be free space with = _o. We are interested in how this structure might be used to guide waves in the y direction and will confine ourselves to fields that are independent of z.

floating figure GIF #23

With a source somewhere to the left (for example an antenna imbedded in the dielectric), there is reason to expect that there are fields outside as well as inside the dielectric. We shall look for field solutions that propagate in the y direction and possess fields solely inside and near the layer. The fields external to the layer decay to zero in the x directions. Like the waves propagating along waveguides, those guided by this structure have transverse components that take the form

equation GIF #13.121

both inside and outside the dielectric. That is, the fields inside and outside the dielectric have the same frequency , the same phase velocity /k_y, and hence the same wavelength 2 /k_y in the y direction. Of course, whether such fields can actually exist will be determined by the following analysis.

The classification of two-dimensional fields introduced in Sec. 12.6 is applicable here. The TM and TE fields can be made to independently satisfy the boundary conditions so that the resulting modes can be classified as TM or TE.


10 Circular dielectric rods do not support simple TE or TM waves; in that case, this classification of modes is not possible. Here we will confine ourselves to the transverse electric modes. In the exterior and interior regions, where the permittivities are uniform but different, it follows from substitution of (1) into (12.6.33) (Table 12.8.3) that

equation GIF #13.122

equation GIF #13.123

A guided wave is one that is composed of a nonuniform plane wave in the exterior regions, decaying in the x directions and propagating with the phase velocity /k_y in the y direction. In anticipation of this, we have written (2) in terms of the parameter _x, which must then be real and positive. Through the continuity conditions, the exterior wave must match up to the interior wave at the dielectric surfaces. The solutions to (3) are sines and cosines if k_x is real. In order to match the interior fields onto the nonuniform plane waves on both sides of the guide, it is necessary that k_x be real.

We now set out to find the wave numbers k_y that not only satisfy the wave equations in each of the regions, represented by (2) and (3), but the continuity conditions at the interfaces as well. The configuration is symmetric about the x = 0 plane so we can further divide the modes into those that have even and odd functions E_z (x). Thus, with A an arbitrary factor, appropriate even solutions to (2) and (3) are

equation GIF #13.124

To simplify the algebra, we have displaced the origin in the exterior solutions so that just the coefficient, A, is obtained when \hat e_z is evaluated at the respective interfaces. With a similar objective, the interior solution has been divided by the constant cos (k_x d) so that at the boundaries, \hat e_z also becomes A. In this way, we have adjusted the interior coefficient so that \hat e_z is continuous at the boundaries.

Because this transverse field is the only component of E, all of the continuity conditions on E are now satisfied. The permeabilities of all regions are presumed to be the same, so both tangential and normal components of H must be continuous at the boundaries. From (12.6.29), the continuity of normal H is guaranteed by the continuity of E_z in any case. The tangential field is obtained using (12.6.30).

equation GIF #13.125

Substitution of (4) into (5) gives

equation GIF #13.126

The assumption that E_z is even in x has as a consequence the fact that the continuity condition on tangential H is satisfied by the same relation at both boundaries.

equation GIF #13.127

Our goal is to determine the propagation constant k_y for a given . If we were to substitute the definitions of _x and k_x into this expression, we would have this dispersion equation, D(,k_y), implicitly relating k_y to . It is more convenient to solve for _x and k_x first, and then for k_y.

Elimination of k_y between the expressions for _x and k_x given with (2) and (3) gives a second expression for _x /k_x.

equation GIF #13.128

The solutions for the values of the normalized transverse wave numbers (k_x d) can be pictured as shown in Fig. 13.5.2. Plotted as functions of k_x d are the right-hand sides of (7) and (8). The points of intersection, k_x d = _m, are the desired solutions. For the frequency used to make Fig. 13.5.2, there are two solutions. These are designated by even integers because the odd modes (Prob. 13.5.1) have roots that interleave these even modes.

floating figure GIF #24

As the frequency is raised, an additional even TE-guided mode is found each time the curve representing (8) reaches a new branch of (7). This happens at frequencies _c such that _x /k_x = 0 and k_x d = m /2, where m = 0, 2, 4, \ldots From (8),

equation GIF #13.129

The m = 0 mode has no cutoff frequency.

To finally determine k_y from these eigenvalues, the definition of k_x given with (3) is used to write

equation GIF #13.130

and the dispersion equation takes the graphical form of Fig. 13.5.3. To make Fig. 13.5.2, we had to specify the ratio of permittivities, so that ratio is also implicit in Fig. 13.5.3.

floating figure GIF #25

Features of the dispersion diagram, Fig. 13.5.3, can be gathered rather simply. Where a mode is just cutoff because = _c, _x = 0, as can be seen from Fig. 13.5.2. From (2), we gather that k_y = _c . Thus, at cutoff, a mode must have a propagation constant k_y that lies on the straight broken line to the left, shown in Fig. 13.5.3. At cutoff, each mode has a phase velocity equal to that of a plane wave in the medium exterior to the layer.

In the high-frequency limit, where goes to infinity, we see from Fig. 13.5.2 that k_xd approaches the constant k_x (m + 1) /2d. That is, in (3), k_x becomes a constant even as goes to infinity and it follows that in this high frequency limit k_y _i.

The physical reasons for this behavior follow from the nature of the mode pattern as a function of frequency. When _x 0, as the frequency approaches cutoff, it follows from (4) that the fields extend far into the regions outside of the layer. The wave approaches an infinite parallel plane wave having a propagation constant that is hardly affected by the layer. In the opposite extreme, where goes to infinity, the decay of the external field is rapid, and a given mode is well confined inside the layer. Again, the wave assumes the character of an infinite parallel plane wave, but in this limit, one that propagates with the phase velocity of a plane wave in a medium with the dielectric constant of the layer.

The distribution of E_z of the m = 0 mode at one frequency is shown in Fig. 13.5.4. As the frequency is raised, each mode becomes more confined to the layer.

floating figure GIF #26

Demonstration 13.5.1. Microwave Dielectric Guided Waves

In the experiment shown in Fig. 13.5.5, a dielectric slab is demonstrated to guide microwaves. To assure the excitation of only an m = 0 TE-guided wave, but one as well confined to the dielectric as possible, the frequency is made just under the cutoff frequency _c2. (For a 2 cm thick slab having _i /o = 6.6, this is a frequency just under 6 GHz.) The m = 0 wave is excited in the dielectric slab by means of a vertical element at its left edge. This assures excitation of E_z while having the symmetry necessary to avoid excitation of the odd modes.

floating figure GIF #27

The antenna is mounted at the center of a metal ground plane. Thus, without the slab, the signal at the receiving antenna (which is oriented to be sensitive to E_z) is essentially the same in all directions perpendicular to the z axis. With the slab, a sharply increased signal in the vicinity of the right edge of the slab gives qualitative evidence of the wave guidance. The receiving antenna can also be used to probe the field decay in the x direction and to see that this decay increases with frequency.

\footnote11To make the excitation independent of z, a collinear array of in-phase dipoles could be used for the excitation. This is not necessary to demonstrate the qualitative features of the guide.