
, satisfies the boundary conditions
= 0 in
the planes y = +a and y = -a.

| (a) | What is in this region?
|
| (b) | Identify p and
h. What boundary conditions are satisfied by h at
y = +a and y = -a?
|
| (c) | Illustrate another combination of p and
h that could just as well be used and give the boundary
conditions that apply for h in that case.
|

(x = 0) = 0 and
(x =
d) = V, so
=
(x) is independent of y and z.

| (a) | Show that Poisson's equation therefore reduces to |
| (b) | Integrate this expression twice and use the boundary
conditions to show that the potential distribution is
![]() |
| (c) | Argue that the first term in (c) can be p, with the
remaining terms then h.
|
| (d) | Show that in that case, the boundary conditions satisfied by
h are
![]() |


| (a) | Show that in |
| (b) | Show that the
surface charge density on the lower surface of the upper electrode is
s = o v/d.
|
| (c) | For a single pair of electrodes, the
capacitance C is defined such that q = Cv (13). Show that for the
plane parallel capacitor of Fig. P5.1.5, C = A o /d, where A is
the area of one of the electrodes.
|
| (d) | Use the integral form of charge
conservation, (1.5.2), to show that i = dq/dt = Cdv/dt.
|
the figure are then approximately E1 = v1/2d, E2 = v2/d and Em = (v1 - v2)/d.
| (a) | Show that the fields denoted in |
| (b) | Show that the net charges q1 and q2 on the top and
middle electrodes, respectively, are related to the voltages by the
capacitance matrix [in the form of (12)]
![]() |

a and
b above and below
the plane y = 0 are

| (a) | Show that (4) holds. (The potential is continuous at y = |
| (b) | Evaluate E tangential to the surface y = 0 and show that it too is continuous. [Equation (1) is then automatically satisfied at y = 0.] |
| (c) | Use (5) to show that in the plane y = 0, the surface
charge density, s = 2 o V cos x, accounts for
the discontinuity in the derivative of normal to the plane y
= 0.
|
guarantees the
continuity of tangential E [(4) implies that (1) is
satisfied], suppose that the potential is given in the plane y = 0:
=
(x, 0, z).
from this information alone?
| (a) | Which components of E can be determined |
| (b) | For example, if (x, 0, z) = V sin ( x) sin
( z), what are those components of E?
|
in the z direction has the
square cross-section of dimensions as shown in Fig. P5.4.1. The walls
at x = 0 and y = 0 are at zero potential, while those at x = a
and y = a have
the linear distributions shown. The interior region is free of charge
density.

| (a) | Show that the potential inside is |
| (b) | Show that plots of and E are as shown in the
first quadrant of Fig. 4.1.3.
|


is zero at x = 0, then C =
0.
cross-section of
length 2a on a side, as shown in Fig. 5.4.2b, is constrained in
potential by resistive sheets and voltage sources, as shown. Note
that the potential is defined to be zero at the lower right-hand corner,
where (x, y) = (a, -a). Inside the cylinder, what must the potential be
in the planes x =
a and y =
a?
| (a) | Suppose a cylindrical region having a square |
| (b) | Find the linear combination of
the potentials from the first column of Table 5.4.1 that satisfies the
conditions on the potentials required by the resistive sheets. That
is, if takes the form
![]() |
| (c) | Determine E for this potential. |
| (d) | Sketch and E.
|
| (e) | Now the potential on the
walls of the square cylinder is constrained as shown in Fig. 5.4.2c.
This time the potential is zero at the location (x, y) = (0, 0). Adjust
the coefficients in (a) so that the potential satisfies these
conditions. Determine E and sketch the equipotentials and field
lines.
|
z directions. There is no charge
density inside the cylinder, and the potentials on the boundaries are



| (a) | Show that the potential inside the cylinder is |
| (b) | Show that a plot of and E is as given by the
part of Fig. 5.4.1 where - /2 < kx < /2.
|
z directions is shown in Fig. P5.4.4. The
potentials on the boundaries are as shown.
Find
.
| (a) | Inside the cylindrical space, there is no charge density. |
| (b) | What is E in this region?
|
| (c) | Sketch and E.
|



is as shown in Fig. P5.4.5.
electrodes is

| (a) | Show that the potential in the region between the |
| (b) | Show that E in this region is
![]() |
| (c) | Show that plots of and E are as shown in
Fig. 5.4.2.
|
| (d) | Show that the net charge on the upper electrode segment
between y = -l and y = l is
![]() |
| (e) | Given that v(t) = Vo sin t, where Vo and
are constants, show that the current to the electrode segment
i(t), as defined in Fig. P5.4.5, is
![]() |
| (a) | Find in the region
|
| (b) | Determine E. |
| (c) | Sketch and E.
|
| (d) | Find the charge q on the electrode segment in the upper middle electrode. |
| (e) | Given that v(t) = Vo cos t, what is i(t)?
|
d (x).
The plates and short have zero potential.
d (x), the potential distribution for 0 < y < b, 0 < x < a is


| (a) | Show that, in terms of |
| (b) | In particular, if the imposed
potential is as shown in Fig. P5.5.1b, show that An is
![]() |

In particular, suppose that these distributions of potential are uniform, so that V1(x) = Va and V2(y) = Vb, with Va and Vb defined to be independent of x and y.
potential distribution there is

| (a) | The region inside the cylinder is free space. Show that the |
| (b) | Show that the distribution of surface charge density along the
wall at x = a is
![]() |

cylinder.
| (a) | Determine the potential in the free space region inside the |
| (b) | Find the surface charge distribution on the wall at y =
b.
|

Show that, far to the left, the potential between the electrodes tends to

| (a) | The electrodes extend to infinity in the -x direction. |
| (b) | Using this result as a part of the solution, a, the
potential between the plates is written as
= a + b. Show that the boundary conditions that
must be satisfied by b are
![]() ![]() ![]() |
| (c) | Show that the potential between the electrodes is
![]() |
| (d) | Show that a plot of and E appears as shown in
Fig. 6.6.9c, turned upside down.
|

d(x).
to the left?
| (a) | What is the potential distribution between the plates far |
| (b) | If is taken as the potential a that
assumes the correct distribution as y - , plus a
potential b, what boundary conditions must be satisfied by
b?
|
| (c) | What is the potential distribution between the plates? |

= (Vy/b) +
1.
must be satisfied by
1 are that
1 = -Vy/b at x = 0
and at x = a, and
1 = 0 at y = 0 and y = b.
| (a) | Show that the boundary conditions that |
| (b) | Show that the potential is
![]() ![]() |
o. On the upper boundary, the
potential is
(x, d, z) = Va sin (
x). On the lower boundary,
(x, 0, z) = Vb sin (
x). Show that
(x, y, z)
throughout the region 0 < y < d is


o, but the
potential at y = d is
=
o sin (kx), while that at y =
0 is zero (
o and k are given constants). Find
in the
region where 0 < y < d, between the boundaries.
d/2 in Fig.
P5.6.3, the charge density is

o and
are given constants. Electrodes at
y =
d/2 constrain the tangential electric field there to be


| (a) | Show that a particular solution is |
| (b) | Show that the total potential is the sum of this solution
and that solution to Laplace's equation that makes the total solution
satisfy the boundary conditions.
![]() |
| (c) | The force density (force per unit volume) acting on the
charge is E. Show that the force fx acting on a section
of the charge of length in the x direction = 2 /k
spanning the region -d/2 < y < d/2 and unit length in the z
direction is
![]() |


o and
are constants. Electrodes at y = d
constrain the potential there to be
(x, d) = Vo cos (kx)
(Vo and k given constants), while an electrode at y = 0 makes
(x, 0) = 0.
everywhere between the electrodes.
| (a) | Find a particular solution that satisfies Poisson's equation |
| (b) | What boundary conditions must the homogeneous solution satisfy at y = d and y = 0? |
| (c) | Find in the region 0 < y < d.
|
| (d) | The force density (force per unit volume) acting on the
charge is E. Find the total force fx acting on a section
of the charge spanning the system from y = 0 to y = d, of unit
length in the z direction and of length = 2 /k in the
x direction.
|

z directions has a
rectangular cross-section of dimensions 2a and b, as shown in Fig.
P5.6.5. The boundaries are at zero potential while the region inside
has the distribution of charge density

o is a given constant. Show that the potential in this
region is



are given constants, what is the charge density
in that region?
| (a) | Given that a particular solution inside the boundaries is |
| (b) | What is ?
|

o x/l. Determine
inside the box, given that
= 0
on the walls.

=
o
cos (
x) e
y, where
o,
, and
are
positive constants. In region (a), where 0 < y,
= 0.

| (a) | Show that a particular solution in the region y < 0 is |
| (b) | There is no surface charge density in the plane y = 0.
Show that the potential is
![]() |
s =
o sin
(x - xo) is in the plane y = 0, as shown
in Fig. 5.6.3. At a distance a above and below the sheet, electrode
structures are used to constrain the potential to be
= V cos
x. The system extends to infinity in the x and z
directions. The regions above and below the sheet are designated (a)
and (b), respectively.
,
o, and xo.
| (a) | Find a and b in terms of the constants V,
|
| (b) | Given that the force per unit area acting on the charge
sheet is s Ex (x, 0), what is the force acting on a section
of the sheet having length d in the z direction and one
wavelength 2 / in the x direction?
|
| (c) | Now, the potential on
the wall is made a traveling wave having a given angular frequency
, (x, a, t) = V cos ( x - t),
and the charge moves to the right with a velocity U, so that
s = o sin (x - Ut - xo), where U =
/ . Thus, the
wall potentials and surface charge density move in synchronism.
Building on the results from parts (a)-(b), what is the potential
distribution and hence total force on the section of charged sheet?
|
| (d) | What you have developed is a primitive model for an
electron beam
device used to convert the kinetic energy of the electrons
(accelerated to the velocity v by a dc voltage) to high-frequency
electrical power
output. Because the system is free of dissipation, the electrical power
output (through the electrode structure) is equal to the mechanical
power input. Based on the force found in part (c), what is the
electrical power output produced by one period 2 / of the
charge sheet of width w?
|
| (e) | For what values of xo would the device act as a generator of electrical power? |
= V
sin 5
. The regions r < a and a < r are free of charge
density. Show that the potential is

measured
relative to the x axis and z the third coordinate axis, the
potential on the surface at r = R is constrained by segmented
electrodes there to be
= V sin
.
region?
| (a) | If = 0 in the region r < R, what is in that
|
| (b) | Over the range r < R, what is the surface charge density on the surface at y = 0? |
= 0 is bounded from outside
at r = a by a surface having the potential
= Va cos 3
and from the inside at r = b by a surface having the potential
= Vb sin
. Show that
in the annulus can be written
as the sum of two terms, each a combination of solutions to Laplace's
equation designed to have the correct value at one radius while being
zero at the other.

<
,
= 0. On the
boundaries of this region at r = a, at
= 0 and
=
,
= 0. At r = b,
= Vb sin (
/
).
Determine
in this region.
<
,
= 0. On the
boundaries of this region at r = a, r = b and at
= 0,
= 0. At
=
, the potential is
= V sin
[3
ln(r/a)/ln(b/a)]. Show that within the region,

= 0 is at potential
= V, while that at
=
3
/2 is at zero potential. The system extends to infinity in the
z and r directions. Determine and sketch
and E
in the range 0 <
< 3
/2.
and E as given by (4) and (5), respectively,
describe the potential and electric field intensity around a perfectly
conducting half-cylinder at r = R on a perfectly conducting plane at
x = 0 with a uniform field Ea ix applied at x
. Show that the maximum field intensity is twice that of the
applied field, regardless of the radius of the half-cylinder.
= Vb > 0. On the outer surface, where r = a,
= Va >
0.
| (a) | What is in the annular region?
|
| (b) | How large must Vb be to insure that all lines of E are outward directed from the inner cylinder? |
| (c) | What is the net charge per unit length on the inner cylinder under the conditions of (b)? |

| (a) | Given o and o, show that in regions (a) and
|
| (b) | Show that the charge on the segment of the inner electrode
attached to the resistor is
![]()
|
| (c) | Given that o = \Omega t, show that the output
voltage is related to \Omega by
![]()
|

= 0 and the other in the plane
=
. They essentially extend to infinity in the
z
directions. Closing the region between the electrodes at r = R is an
electrode having potential V. Show that the potential inside the
region bounded by these three surfaces is

= 0 plane by a grounded electrode and in the
=
plane by one that has
= V. The region extends to
infinity in the r direction. At r = R,
= V. Determine
.
= 0 that reaches from
the wall to the center. The gaps between the cylinder and the fin are
very small.
the boun\-dary conditions at
= 0 and
= 2
. Note
that you cannot accept solutions for
of negative powers in
r.
| (a) | Find all solutions in polar coordinates that satisfy |
| (b) | Match the boundary condition at r = R. |
| (c) | One of the terms in this solution
has an electric field intensity that is infinite at the tip of the
fin, where r = 0. Sketch and E in the neighborhood of the
tip. What is the s on the fin associated with this term as
a function of r? What is the net charge associated with this term?
|
| (d) | Sketch the potential and field intensity throughout the region. |

= 0 has the
potential v. The wall at
=
o is grounded. Determine the
interior potential.
= V cos
.
or inside this shell, what is
for r < a and for r > a?
| (a) | With no charge density either outside |
| (b) | Sketch and E.
|
o cos
.
volume of interest, the potential is

| (a) | Show that if this is the only charge in the |
| (b) | Show that a plot of and E appears as shown in
Fig. 6.3.1.
|
=
o cos
. Show that the
potential there is

=
o (r/a)m cos
, where
o and m
are given constants. If the potential
= 0 at r = a, what is
for r < a?
= v.
Show that


s =
o sin (
x/a) sin (
z/w). Find the
potentials
a and
b above and below this surface,
respectively.
=
o. Write four essentially
different expressions for the potential distribution.

1 and
2 defined in the figure and then
convert the representation to Cartesian coordinates to show that

