| Laws and Continuity Conditions with Magnetization |
9.2.1 |
Return to Prob. 6.1.1 and replace P M. Find
m and sm.
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9.2.2* | A circular cylindrical rod of material is uniformly magnetized in the
y' direction transverse to its axis, as shown in Fig. P9.2.2.
Thus, for r < R, M = Mo [ix sin + iy cos
]. In the surrounding region, the material forces H to be
zero. (In Sec. 9.6, it will be seen that such a
material is one of infinite permeability.)
Figure P9.2.2
Figure P9.2.3
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9.2.3 | In a region between the planes y = a and y = 0, a material that moves
in the x direction with velocity U has the magnetization density
M = Mo iy cos (x - Ut), as shown in Fig. P9.2.2. The
regions above and below are constrained so that H = 0 there and so
that the integral of H ds between y = 0 and y = a
is zero. (In
Sec. 9.7, it will be clear that these materials could be the pole
faces of a highly permeable magnetic circuit.)
(a) | Show that Ampère's law and (9.2.2) are satisfied if H = 0 throughout the magnetizable
layer of material.
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(b) | A one-turn rectangular coil is located in the
y = 0 plane, one leg running in the +z direction at x = -d (from
z = 0 to z = l) and another running in the -z direction at x =
d (from z = l to z = 0). What is the voltage induced at the
terminals of this coil by the motion of the layer?
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| Permanent Magnetization |
9.3.1* | The magnet shown in Fig. P9.3.1 is much longer in the z
directions than either of its cross-sectional dimensions 2a and 2b.
Show that the scalar magnetic potential is
(Note Example 4.5.3.)
Figure P9.3.1
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9.3.2* | In the half-space y > 0, M = Mo cos ( x) exp (-
y)iy, where and are given positive constants.
The half-space y < 0 is free space. Show that
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9.3.3 | In the half-space y < 0, M = Mo sin ( x) exp (
y)ix, where and are positive constants.
The half-space y > 0 is free space. Find the scalar magnetic
potential.
Figure P9.3.4
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9.3.4 | For storage of information, the cylinder shown
in Fig. P9.3.4 has the magnetization density
where p is a given integer. The surrounding region is free space.
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| Magnetization Constitutive Laws |
9.4.1* | The toroidal core of Example 9.4.1 and Demonstration 9.4.1 is
filled by a material having the single-valued magnetization
characteristic M = Mo tanh ( H), where M and H
are collinear.
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9.4.2 | The toroidal core of Demonstration 9.4.1 is driven by a
sinusoidal current i(t) and responds with the hysteresis
characteristic of Fig. 9.4.6. Make qualitative sketches of the time
dependence of
(a) | B(t)
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(b) | the output voltage v(t).
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| Fields in the Presence of magnetically Linear Insultating Materials |
9.5.1* | A perfectly conducting sheet is bent into a shape to make a
one-turn inductor, as shown in Fig. P9.5.1. The width w is much
larger than the dimensions in the x - y plane. The region inside the
inductor is filled with two linearly magnetizable materials having
permeabilities a and b, respectively. The
cross-section of the system in any x - y plane is the same. The
cross-sectional areas of the magnetizable materials are Aa and
Ab, respectively. Given that the current i(t) is uniformly
distributed over the width w of the inductor, show that
H = (i/w)iz in both of the magnetizable materials. Show
that the inductance L = (a Aa + b Ab)/w.
Figure P9.5.1
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9.5.2 | Perfectly conducting coaxial cylinders, shorted at one end, form
the one-turn inductor shown in Fig. P9.5.2. The total current i
flowing on the surface at r = b of the inner cylinder is returned
through the short and the outer conductor at r = a. The annulus is
filled by materials of uniform permeability with an interface at r =
R, as shown.
Figure P9.5.2
(a) | Determine H in the annulus. (A simple solution can be shown to satisfy all the laws and continuity conditions.)
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(b) | Find the inductance.
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9.5.3* | The piece-wise uniform material in the one-turn inductor of Fig.
P9.5.1 is replaced by a smoothly inhomogeneous material having the
permeability = - m x/l, where m is a given
constant. Show that the inductance is L = dm l/2w.
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9.5.4 | The piece-wise uniform material in the one-turn inductor of Fig.
P9.5.2 is replaced by one having the permeability = m (r/b),
where m is a given constant. Determine the inductance.
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9.5.5* | Perfectly conducting coaxial cylinders, shorted at one end, form
a one-turn inductor as shown in Fig. P9.5.5. Current flowing on the
surface at r = b of the inner cylinder is returned on the inner surface
of the outer cylinder at r = a. The annulus is filled by sectors of
linearly magnetizable material, as shown.
Figure P9.5.5
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9.5.6 | In the one-turn inductor of Fig. P9.5.1, the material of
piece-wise uniform permeability is replaced by another such material.
Now the region between the plates in the range 0 < z < a is filled by
material having uniform permeability a, while = b in
the range a < z < w. Determine the inductance.
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| Fields in Piece-Wise Uniform Magnetically Linear Materials |
9.6.1* | A winding in the y = 0 plane is used to produce the surface current
density K = Ko cos z ix. Region (a), where y > 0,
is free space, while region (b), where y < 0, has permeability .
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9.6.2 | The planar region -d < y < d is bounded from above and below by
infinitely permeable materials, as shown in Fig. P9.6.2. Region (a)
to the right and region (b) to the left are separated by a current
sheet in the plane x = 0 with the distribution K = iz Ko
sin ( y/2d). The system extends to infinity in the x
directions and is two dimensional.
Figure P9.6.2
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9.6.3* | The cross-section of a two-dimensional cylindrical system is
shown in Fig. P9.6.3. A region of free space having radius R is
surrounded by material having permeability which can be
considered as extending to infinity. A winding at r = R is driven by
the current i and has turns density (N/2R) sin (turns per
unit length in the direction). Thus, at r = R, there is a
current density K = (N/2R) i sin iz.
(a) | Show that
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(b) | An n-turn coil having a spacing between conductors of 2a
is now
placed at the center. The magnetic axis of this coil is inclined at
the angle relative to the x axis. This coil has length l in
the z direction. Show that the mutual inductance between this coil and
the one at r = R is Lm = o a ln N cos /R[1 + (o
/ )].
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Figure P9.6.3
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9.6.4 | The cross-section of a motor or generator is shown in Fig.
11.7.7. The two coils comprising the stator and rotor windings and
giving rise to the surface current densities of (11.7.24) and
(11.7.25) have flux linkages having the forms given by (11.7.26).
infinite, and determine the vector potential in the air gap.
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9.6.5 | A wire carrying a current i in the z direction is suspended
a height h above the surface of a magnetizable material, as shown in
Fig. P9.6.5. The wire extends to "infinity" in the z directions.
Region (a), where y > 0, is free space. In region (b), where y < 0,
the material has uniform permeability .
images to determine the fields in the two regions.
Figure P9.6.5
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9.6.6* | A conductor carries the current i(t) at a height h above the
upper surface of a material, as shown in Fig. P9.6.5. The force per
unit length on the conductor is f = i x o H, where
i is a vector having the direction and magnitude of the current
i(t), and H does not include the self-field of the line current.
f = o iy i2/4 h.
(a) | Show that if the material is a perfect conductor,
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(b) | Show that if the material is infinitely permeable, f
= - o iy i2/4 h.
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9.6.7* | Material having uniform permeability is bounded from above
and below by regions of infinite permeability, as shown in Fig.
P9.6.7. With its center at the origin and on the surface of the lower
infinitely permeable material is a hemispherical cavity of free space
having radius a that is much less than d. A field that has the uniform
intensity Ho far from the hemispherical surface is imposed in the
z direction.
approximate magnetic potential in the magnetizable material is
= - Ho a[(r/a) + (a/r)2/2] cos .
Figure P9.6.7
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9.6.8 | In the magnetic tape configuration of Example 9.3.2, the system
is as shown in Fig. 9.3.2 except that just below the tape, in the
plane y = -d/2, there is an infinitely permeable material, and in the
plane y = a > d/2 above the tape, there is a second infinitely permeable
material. Find the voltage vo.
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9.6.9* | A cylindrical region of free space of rectangular cross-section
is surrounded by infinitely permeable material, as shown in Fig.
P9.6.9. Surface currents are imposed by means of windings in the
planes x = 0 and x = b. Show that
Figure P9.6.9
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9.6.10* | A circular cylindrical hole having radius R is cut through a
material having permeability a. A conductor passing through
this hole has permeability b and carries the uniform current
density J = Jo iz, as shown in Fig. P9.6.10. A field that
is uniform far from the hole, where it is given by H = Ho ix,
is applied by external means. Show that for r < R, and R < r,
respectively,
Figure P9.6.10
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9.6.11* | Although the introduction of a magnetizable sphere into a uniform
magnetic field results in a distortion of that field, nevertheless,
the field within the sphere is uniform. This fact makes it possible
to determine the field distribution in and around a spherical particle
even when its magnetization characteristic is nonlinear. For example,
consider the fields in and around the sphere of material shown
together with its B-H curve in Fig. P9.6.11.
where M is a constant to
be determined, and show that the magnetic field intensity inside the
sphere is uniform, z directed, and of magnitude H = Ho - M/3, and
hence that the magnetic flux density, B, in the sphere is related to the
magnitude of the magnetic field intensity H by
(a) | Assume that the magnetization density is M = M iz,
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(b) | Draw this load line in the B-H plane, showing that it
is a straight line with intercepts 3Ho/2 and 3o Ho with the H
and B axes, respectively.
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(c) | Show how (B, H) in the sphere are
determined, given the applied field intensity Ho, by graphically
finding the point of intersection between the B - H curve of Fig.
P9.6.11 and (a).
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(d) | Show that if Ho = 4 x 105 A/m, B = 0.75 tesla
and H = 3.1 x 105 A/m.
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Figure P9.6.11
Figure P9.6.12
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9.6.12 | The circular cylinder of magnetizable material shown in Fig.
P9.6.12 has the B - H curve shown in Fig. P9.6.11. Determine B and
H inside the cylinder resulting from the application of a field
intensity H = Ho ix where Ho = 4 x 105 A/m.
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9.6.13 | The spherical coil of Example 9.6.1 is wound around a sphere of
material having the B - H curve shown in Fig. P9.6.11. Assume that
i = 800 A, N = 100 turns, and R = 10 cm, and determine B and
H in the material.
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| Magnetic Circuits |
9.7.1* | The magnetizable core shown in Fig. P9.7.1 extends a distance d
into the paper that is large compared to the radius a. The driving
coil, having N turns, has an extent in the direction that
is small compared to dimensions of interest. Assume that the core has
a permeability that is very large compared to o.
(with defined to be zero at = ) are
(a) | Show that the approximate H and inside the core
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(b) | Show that the approximate magnetic potential in the central
region is
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Figure P9.7.1
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9.7.2 | For the configuration of Prob. 9.7.1, determine in the
region outside the core, r > a.
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9.7.3* | In the magnetic circuit shown in Fig. P9.7.3, an N-turn coil is
wrapped around the center leg of an infinitely permeable core. The
sections to right and left have uniform permeabilities a and
b, respectively, and the gap lengths a and b are small compared
to the other dimensions of these sections. Show that the inductance
L = N2 w[(b d/b) + (a c/a)].
Figure P9.7.3
Figure P9.7.4
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9.7.4 | The magnetic circuit shown in Fig. P9.7.4 is constructed from
infinitely permeable material, as is the hemispherical bump of
radius R located on the surface of the lower pole face. A coil,
having N turns, is wound around the left leg of the magnetic circuit.
A second coil is wound around the hemisphere in a distributed fashion.
The turns per unit length, measured along the periphery of the
hemisphere, is (n/R) sin , where n is the total number of turns.
Given that R h w, find the mutual inductance of the two coils.
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9.7.5* | The materials comprising the magnetic circuit of Fig. P9.7.5 can
be regarded as having infinite permeability. The air gaps have a
length x that is much less than a or b, and these dimensions, in
turn, are much less than w. The coils to left and right, respectively,
have total turns N1 and N2. Show that the self- and mutual
inductances of the coils are
Figure P9.7.5
Figure P9.7.6
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9.7.6 | The magnetic circuit shown in Fig. P9.7.6 has rotational symmetry
about the z axis. Both the circular cylindrical plunger and the
remainder of the magnetic circuit can be regarded as infinitely
permeable. The air gaps have widths x and g that are small
compared to a and d. Determine the inductance of the coil.
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9.7.7 | Two cross-sectional views of an axisymmetric magnetic circuit
that could be used as an electromechanical transducer are shown in
Fig. P9.7.7. Surrounding an infinitely permeable circular
cylindrical rod having a radius slightly less than a is an
infinitely permeable stator having a hole down its center with a
radius slightly greater than a. A pair of coils, having
turns N1 and N2 and driven by currents i1 and i2,
respectively are wound around the center rod and positioned in slots
in the surrounding stator. The longitudinal position of the rod,
denoted by , is limited in range so that the ends of the rod are
always well inside the ends of the stator. Thus, H in each of
the air gaps is essentially uniform. Determine the inductance
matrix, (9.7.12).
Figure P9.7.7
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9.7.8 | Fields in and around the magnetic circuit shown in Fig. P9.7.8
are to be considered as independent of z. The outside walls are
infinitely permeable, while the horizontal central leg has uniform
permeability that is much less than that of the sides but
nevertheless much greater than o. Coils having
total turns N1 and N2, respectively, are wound around the
center leg. These have evenly distributed turns in the planes x =
l/2 and x = -l/2, respectively. The regions above and below the
center leg are free space.
coordinates. As far as is concerned inside the center leg,
what boundary conditions must satisfy if the central leg is
treated as the "inside" of an "inside-outside" problem?
Figure P9.7.8
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9.7.9 | The magnetic circuit shown in Fig. P9.7.9 is excited by an N-turn
coil and consists of infinitely permeable legs in series with
ones of permeability , one to the right of length l2 and the
other to the left of length l1. This second leg has
wrapped on its periphery a metal strap having thickness
w, conductivity , and height l1. With a terminal current
i = io cos t, determine H within the left leg.
Figure P9.7.9
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9.7.10* | The graphical approach to determining fields in magnetic circuits
to be used in this and the next example is similar to that
illustrated by Probs. 9.6.11-9.6.13. The magnetic circuit of a
high-field magnet is shown in Fig. P9.7.10. The two coils each have
N turns and carry a current i.
(a) | Show that the load line for the circuit is
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(b) | For N = 500, d = 1 cm, l1 = 0.8 m,
l2 = 0.2 m, and i = 10 amps, find the flux density B in its
air gap.
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Figure P9.7.10
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9.7.11 | In the magnetic circuit of Fig. P9.7.11, the infinitely permeable
core has a gap with cross-sectional area A and height a + b, where
the latter is much less than the dimensions of the former. In this
gap is a material having height b and the M - H relation also
shown in the figure. Within the material and in the air gap, H is
approximated as being uniform.
the field intensity in the material, M, and the driving current i.
(a) | Determine the load line relation between Hb,
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(b) | If Ni/a = 0.5 x 106 amps/m and b/a = 1, what is
M, and hence B?
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Figure P9.7.11
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