Problems 3.9 - 3.16 3.9 Functions of random variables (derived distributions) Consider a square service region of unit area in which travel is right-angle and directions of travel are parallel to the sides of the square. Let (X1, Y1) be the location of a mobile unit and (X2, Y2) the location of a demand for service. The travel distance is D = Dx + Dy where Dx = |X1 - X2| and Dy = |Y1 - Y2| We assume that the two locations are independent and uniformly distributed over the square.
3.10 Ratio of right-angle and Euclidean travel
distances In this problem
we test the reasonableness of the isotropy assumption used in
Example 4. It is appropriate
to question this assumption since most service regions in a city are
such that
(Intuition is correct but the result is closer to 4/
3.11 Quantization model (continued) In Example 5 we described a quantization model for odometer readings. We stated that [(3.31)] Prove these results. What implications do these results have for an actual datagathering experiment?
3.12 Truncated times Assume that an
activity commences at
time T1 and terminates at time T2. The exact duration of the
activity is T2
- T1, 3.13 Zero-demand zone Consider a
unit-square response area,
as shown in Figure P3.13(a). We assume that a response unit and
incident (i.e., requests
for service) are distributed uniformly, independently over that part
of the unit square
not contained within the central square having area a2. Travel
occurs according to the
right-angle metric, and travel is allowed through the zero-demand
zone. We want to use
conditioning arguments to derive the expected travel distance W(a)
to a random incident. Now focus on a unit square on which incidents and the response unit are uniformly, independently distributed over the entire square, yielding an expected travel distance E[D]. c. Finally, find W(a). As a check, W(0) = 2/3, W(1) = 11/12. (Why?) 3.14 Square barrier Suppose that the conditions of Problem 3.13 apply, except that in addition, no travel is allowed through the central square. We wish to derive W'(a) = expected travel distance to a random incident We use perturbation arguments to write W"(a) = W(a) + WE,(a) where W(a) is the mean travel distance from Problem 3.13 and WE(a) is the mean extra (perturbation) distance due to the barrier. As a check, verify the reasonableness of the result W'(l) = 1. 3.15 Rectangular grid of two-way streets Consider an n x m rectangular grid of two-way streets running north-south and east- west as shown in Figure P3.15. Assume that incident positions are distributed uniformly over the grid. A response unit patrols the grid in a uniform manner. The incident location and the response unit location are independent. Let D = travel distance between the response unit and the incident, assuming the unit follows a shortest path that remains on the streets of the grid
3.16 Perturbation variables: one-way streets Consider a very large grid of equally spaced one-way streets, with the direction of travel alternating from street to adjacent parallel street. Assume that the positions of the response unit and the incident are independent and uniformly distributed over the grid. It is assumed that the response distance -from the response unit to the incident is a shortest path that remains on the streets of the grid and obeys the one-way constraints. Use perturbation variables to demonstrate that the mean extra distance traveled to the incident, due to the one-way travel constraints, is two blocks.
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