Distributed Parameter Equivalents and Models with Dissipation

The distributed parameter transmission line of Sec. 14.1 is now generalized to include certain types of dissipation by using the incremental circuit shown in Fig. 14.7.1 . The capacitance per unit length

Cis shunted by a conductance per unit lengthGand in series with the inductance per unit lengthLis the resistance per unit lengthR.

Fig 14.7.1Incremental section of lossy distributed line.If the line really were made up of so many lumped parameter elements that it could be described by continuum equations,

Gwould be the conductance per unit length of the lossy capacitors (Sec. 7.9) andRwould be the resistance per unit length of the inductors. More often,GandR(likeLandC) are either equivalent to or a model of a physical system. Examples are discussed in the next two sections.The steps leading to the generalized transmission line equations are suggested by Eqs. 14.1.1 through 14.1.5. In requiring that the currents at the terminal on the right sum to zero, there is now an additional current through the shunt conductance. In the limit where

z 0,

Similarly, in summing the voltages around the loop, there is now a voltage drop across the series resistance. Again, in the limit

z 0,

As should be expected, with the introduction of dissipation represented by

GandR, V(z, t)andI(z, t)no longer take the form of waves propagating without distortion. That is, substitution shows that solutions no longer take the form of (14.4.1)-(14.4.3). As a result, we would have to work considerably harder than in Secs. 14.3-14.4 to describe transients on lossy transmission lines. However, although somewhat more involved then before, the sinusoidal steady state response follows from the approach illustrated in Secs. 14.5-14.6.With the objective of describing the sinusoidal steady state, complex amplitude representations of

VandI(14.5.2) are substituted into (1) and (2) to give

To obtain an expression for the voltage alone, (3) is substituted into the derivative of (4).

With the voltage found from this equation, the current follows from (4).

Albeit complex, the coefficient in (5) is constant, so it is again appropriate to look for exponential solutions. Using the convention established in Sec. 14.5, we look for solutions

exp (-jkz). Substitution into (5) then shows that

So as to be clear in distinguishing the two roots of this dispersion equation, we

defineas having a positive real part and write the roots as

These roots,

k = k, are pictured as a function of frequency in Fig. 14.7.2. From (7),_{r}+ jk_{i}kis in the lower half-plane. It follows that the value of^{2}khaving a positive real part (defined as ) has a negative imaginary part.

Fig 14.7.2Roots of (7) as functions of normalized . The real and imaginary parts, respectively, of the complex wave number relate to the phase velocity and rate of decay of the wave, as shown.These definitions take on physical significance when the solutions to (5) are written as

because it is then clear that we have defined so that

Vrepresents a wave with points of constant phase propagating in the_{+}+zdirection. Note that becauseis negative, this wave decays in the_{i}+zdirection, as shown in Fig. 14.7.2. Similarly,is the complex amplitude at_{-}z = 0of a wave that decays in the-zdirection and has phases propagating in the-zdirection.

In terms of the two coefficients

, the current expression follows from substituting (9) into (6)_{}

where the complex characteristic impedance is now defined as

Comparison of (9) and (10) with (14.5.5) and (14.5.6) shows that the impedance and reflection coefficient descriptions are applicable, provided we generalize and

Zto be the complex numbers given by (8) and (11). That these quantities are now complex is an inconvenience_{o}

The lossy transmission line shown in Fig. 14.7.3 is open at the right and driven by a voltage source of complex amplitude

Vat the left. What is the voltage measured at the open circuit?_{g}

Fig 14.7.3Open circuit lossy line.The open circuit at

z = 0requires thatI(0) = 0, and hence [from (10)] thatV. Thus, the voltage, as given by (9), is_{+}= V_{-}

Here we have adjusted the coefficient

so that the voltage is_{+}at the left end, where the voltage source is connected. As a function of time, the voltage distribution is therefore_{g}

Much of the complicated phenomenon represented by this simple expression is encapsulated in the complex wave number. To illustrate, consider the voltage measured at

z = 0, which from (13) has the complex amplitude

If a calculator or computer is not available for evaluating the cosine of a complex number, then we can use the double-angle identity to write

For the case where all of the loss is due to the shunt conductance

(R = 0), the frequency response is illustrated in Fig. 14.7.4. The four responses shown are for increasing amounts of loss, perhaps introduced by increasingG.

Fig 14.7.4Frequency response for open circuit lossy line.At very low frequencies, the output voltage simply follows the driving voltage. This is because we have considered the case where

R = 0and with the frequency so low that the inductor has no effect, the output terminals are connected to the source through a negligible impedance.

As the frequency is raised, consider first the response with no loss

(l/l. As the frequency approaches that required to make the line a quarter-wavelength long, the impedance of the line at the generator approaches zero and the current approaches infinity. This resonance condition results in the infinite response at^{*}= 0)z = 0. (As the frequency is raised further, these resonance conditions occur each time the frequency is such that the line has a length equal to a quarter-wavelength plus a multiple of a half-wavelength.) With the addition of a slight amount of loss(l/l, the response is finite even under the resonance conditions. Further increasing the loss (^{*}= 0.1)l/l) results in a response with a dull peak at the resonance point. Still larger losses (^{*}= 1l/l) bring in skin effect and monotonic attenuation of the voltage over the length of the line. Phenomena underlying this response are discussed in the next section.^{*}= 10