The law relating the magnetic field intensity H to its
source, the current density J, is
Note that by contrast with the integral statement of Gauss' law,
(1.3.1), the surface integral symbols on the right do not have circles.
This means that the integrations are over open surfaces, having edges
denoted by the contour C. Such a surface S enclosed by a contour C is
shown in Fig. 1.4.1. In words, Ampère's integral law as given by (1)
requires that the line
integral (circulation) of the magnetic field
intensity H around a closed contour is equal to the net current
passing through the surface spanning the contour plus the time rate of
change of the net displacement flux density
o E through the
surface (the displacement current).
Figure 1.4.1. Surface S is enclosed by contour
C having positive direction determined by the right-hand rule.
With the fingers in the direction of ds, the thumb passes through
the surface in the direction of positive da.
The direction of positive da is determined by the right-hand rule,
as also illustrated in Fig. 1.4.1. With the fingers of the right-hand
in the direction of ds, the thumb has the direction of da.
Alternatively, with the right hand thumb in the direction of ds,
the fingers will be in the positive direction of da.
In Ampère's law, H appears without
o. This law
therefore establishes the basic units of H as
coulomb/(meter-second). In Sec. 1.1, the units of the flux density
o H are defined by the Lorentz force, so the second empirical
constant, the permeability of free space, is
o = 4
x 10-7 henry/m (henry = volt sec/amp).
Example 1.4.1. Magnetic Field Due to Axisymmetric Current
A constant current in the z direction within the circular
cylindrical region of radius R, shown in Fig. 1.4.2, extends from -
infinity to + infinity along the z axis and is represented by the
density
where Jo and R are given constants. The associated magnetic field
intensity has only an azimuthal component.
Figure 1.4.2. Axially symmetric current
distribution and associated radial distribution of azimuthal magnetic
field intensity. Contour C is used to determine azimuthal H,
while C' is used to show that the z-directed field must be
uniform.
To see that there can be no r component of this field, observe that
rotation of the source around the radial axis, as shown in Fig. 1.4.2,
reverses the source (the current is then in the -z direction) and
hence must reverse the field. But an r component of the field does
not reverse under such a rotation and hence must be zero. The
H
and Hz components are not ruled out by this argument.
However, if they
exist, they must not depend upon the
and z coordinates, because
rotation of the source around the z axis and translation of the source
along the z axis does not change the source and hence does not change
the field.
The current is independent of time and so we assume that the
fields are as well. Hence, the last term in (1), the displacement
current, is zero. The law is then used with S, a surface having its
enclosing contour C at the arbitrary radius r, as shown in Fig. 1.4.2.
Then the area and line elements are
and the right-hand side of (1) becomes
Integration on the left-hand side amounts to a multiplication of the
independent H
by the length of C.
These last two expressions are used to evaluate (1) and obtain
Thus, the azimuthal magnetic field intensity has the radial
distribution shown in Fig. 1.4.2.
The z component of H is, at most, uniform. This can be seen by
applying the integral law to the contour C', also shown in
Fig. 1.4.2. Integration on the top and bottom legs gives zero
because Hr = 0. Thus,
to make the contributions due to Hz on the vertical legs cancel, it is
necessary that Hz be independent of radius. Such a uniform field must
be caused by sources at infinity and is therefore set equal to zero
if such sources are not postulated in the statement of the problem.
The first of two singular forms of the
current density shown in Fig. 1.4.3a is the line current.
Formally, it
is the limit of an infinite current density distributed over an
infinitesimal area.
With i a constant over the length of the line, a thin wire carrying a
current i conjures up the correct notion of the line current. However,
in general, the current i may depend on the position along the line
if it varies with time as in an antenna.
Figure 1.4.3. (a) Line current enclosed by volume
having cross-sectional area A. (b) Surface current density
enclosed by contour having thickness h.
The second singularity, the surface current density, is the limit
of a very large current density J distributed over a very thin layer
adjacent to a surface. In Fig. 1.4.3b, the current is in a direction
parallel to the surface. If the layer extends between
= -h/2 and
= +h/2, the surface current density K is defined as
By definition, K is a vector tangential to the surface that has
units of ampere/meter.
Figure 1.4.4. Uniform line current with
contours for determining H. Axis of rotation is used to deduce
that radial component of field must be zero.
Illustration. H field Produced by a Uniform Line Current
A uniform line current of magnitude i extends from - infinity to
+ infinity along the z axis, as shown in Fig. 1.4.4. The symmetry
arguments of Example 1.4.1 show that the only component of H is
azimuthal. Application of Ampère's integral law, (1), to the contour
of Fig. 1.4.4 having arbitrary radius r gives a line integral that is
simply the product of H
and the circumference 2
r and a
surface integral that is simply i, regardless of the radius.
This expression makes it especially clear that the units of H are
ampere/meter.
At 60 Hz, the displacement current contribution to the magnetic
field of the experiment shown in Fig. 1.4.5 is negligible. So long as
the field probe is within a distance r from the wire that is small
compared to the distance to the ends of the wire or to the return
wires below, the magnetic field intensity is predicted quantitatively
by (10). The curve shown is typical of demonstration measurements
illustrating the radial dependence. Because the Hall-effect probe
fundamentally exploits the Lorentz force law, it measures the flux
density
oH. A common unit for flux density is the Gauss. For
conversion of units, 10,000 gauss = 1 tesla, where the tesla is the
SI unit.
Figure 1.4.5. Demonstration of peak magnetic flux
density induced by line current of 6 ampere (peak).
Illustration. Uniform Axial Surface Current
At the radius R from the z axis, there is a uniform z directed
surface current density Ko that extends from - infinity to +
infinity in the z direction. The symmetry arguments of Example
1.4.1 show that the resulting magnetic field intensity is azimuthal.
To determine that field, Ampère's integral law is applied to a
contour having the arbitrary radius r, shown in Fig. 1.4.6. As in
the previous illustration, the line integral is the product of the
circumference and H
. The surface integral gives nothing if r
< R, but gives 2
R times the surface current density if r >
R. Thus,
Figure 1.4.6. Uniform current density Ko
is z directed in circular cylindrical shell at r = R. Radially
discontinuous azimuthal field shown is determined using the contour
at arbitrary radius r.
Thus, the distribution of H
is the discontinuous function
shown in Fig. 1.4.6. The field tangential to the surface current
undergoes a jump that is equal in magnitude to the surface current
density.
A surface current density in
a surface S causes a discontinuity of the magnetic field intensity.
This is illustrated in Fig. 1.4.6. To obtain a general relation
between fields evaluated to either side of S, a rectangular surface of
integration is mounted so that it intersects S as shown in Fig.
1.4.7. The normal to S is in the plane of the surface of integration.
The length l of the rectangle is assumed small enough so that the
surface of integration can be considered plane over this length. The
width w of the rectangle is assumed to be much smaller than l . It is
further convenient to introduce, in addition to the normal n to S,
the mutually orthogonal unit vectors is and in as shown.
Figure 1.4.7. Ampère's integral law is applied
to surface S' enclosed by a rectangular contour that
intersects a surface S carrying the current density K. In
terms of the unit normal to S, n, the resulting continuity
condition is given by (16).
Now apply the integral form of Ampère's law, (1), to the
rectangular surface of area lw. For the right-hand side we obtain
Only J gives a contribution, and then only if there is an infinite
current density over the zero thickness of S, as required by the
definition of the surface current density, (9). The time rate of
change of a finite displacement flux density integrated over zero
area gives zero, and hence there is no contribution from the second
term.
The left-hand side of Ampère's law, (1), is a contour integral
following the rectangle. Because w has been assumed to be very
small compared with l, and H is assumed finite, no contribution
is made by the two short sides of the rectangle. Hence,
From Fig. 1.4.7, note that
The cross and dot can be interchanged in this scalar triple product
without affecting the result (Appendix 1), so introduction of
(14) into (13) gives
Finally, note that the vector in is arbitrary so long as it
lies in the surface S. Since it multiplies vectors
tangential to the surface, it can be omitted.
There is a jump in the
tangential magnetic field intensity as one passes through a surface
current. Note that (16) gives a prediction consistent with what was
found for the illustration in Fig. 1.4.6.