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2.3 Binormal vector and torsion
Figure 2.6:
The tangent, normal, and binormal vectors define an orthogonal
coordinate system along a space curve
In Sects. 2.1 and 2.2, we
have introduced the tangent and normal vectors, which are orthogonal
to each other and lie in the osculating plane. Let us define a unit
binormal vector
such that
form
a right-handed screw, i.e.
(2.40)
which is shown in Fig. 2.6.
The plane defined by normal and binormal vectors is called the
normal plane and the plane defined by binormal and tangent vectors
is called the rectifying plane (see Fig. 2.6).
As mentioned before, the plane defined by tangent
and normal vectors is called the osculating plane. The binormal
vector for the arbitrary speed curve with nonzero curvature can be
obtained by using (2.23) and the first equation of
(2.40) as follows:
(2.41)
The binormal vector is perpendicular to the osculating plane and its
rate of change is expressed by the vector
(2.42)
where we used the fact that
.
Since
is a unit vector
, we have
. Therefore
is parallel to
the rectifying plane (
), and hence
can be
expressed as a linear combination of
and
:
(2.43)
Thus, using (2.42) and (2.43), we obtain
(2.44)
The coefficient
is called the torsion and measures how
much the curve deviates from the osculating plane. By
taking the dot product with
, we obtain the torsion of the
curve at a nonzero curvature point
(2.45)
where (2.20) is used and
is a triple scalar product.2.1
The torsion for an arbitrary speed curve is given by
(2.48)
The evaluation of torsion when curvature vanishes is discussed in
Sect. 6.2.
While the curvature is determined only in magnitude, except for
plane curves, torsion is determined both in magnitude and sign.
Torsion is positive when the rotation of the osculating plane is in the
direction of a right-handed screw moving in the direction of
as
increases. If the torsion is zero at all points, the curve is
planar.
The binormal vector of a 3-D implicit curve can be obtained from
(2.38) as follows:
(2.49)
The torsion for a 3-D implicit curve can be derived by applying the
derivative operator (2.31) to
(2.38) [444], which gives
(2.50)
and therefore
(2.51)
Taking the dot product with (2.37) we obtain
(2.52)
from which we calculate
. An alternative approach for evaluating
the torsion of 3-D implicit curves is presented in Sect.
6.3.3.
Example 2.3.1
A circular helix in parametric representation is given
by
. Figure 2.7 shows a circular helix with
,
for
. The
parametric speed is easily computed as
, which is a constant. Therefore the curve is regular and
its arc length is
We can easily reparametrize the curve with arc length by replacing
by
yielding
. The first three derivatives are evaluated as
The curvature and torsion are evaluated as follows:
Note that the circular helix has constant curvature and torsion and
when
, it is a right-handed helix
while when
, it is a left-handed helix.