User’s Guide, Chapter 10: Examples 1

Well, that’s long enough to go without doing some actual work! Let’s see what is possible to do so far.|

Where do Chords move to?

Let’s take our favorite work so far, Bach’s BWV 66.6, and see where each chord goes.

We’ll begin, as always, with importing music21 and parsing the work from the corpus.

from music21 import *
s = corpus.parse('bwv66.6')

Now let’s chordify it.

sChords = s.chordify()
sChords
 <music21.stream.Part Soprano>

sChords is a Part containing no Chords! It has measures, which contain Chords. We’re going to want to see all the chords, so let’s flatten it with .flat.

sFlat = sChords.flat
sFlat
 <music21.stream.Part Soprano_flat>

Inside sChords is not just chords, but also the time signatures, etc., so let’s create a Stream that only has the chords in sChords. And we’ll get rid of all internal barlines, measures, etc. We’ll use .getElementsByClass('Chord') for that:

sOnlyChords = sFlat.getElementsByClass('Chord')
sOnlyChords
 <music21.stream.iterator.StreamIterator for Part:Soprano_flat @:0>

We are eventually going to want to display each chord, so we’ll create a new Stream to do so. We’ll make it a Part object:

displayPart = stream.Part(id='displayPart')
displayPart
 <music21.stream.Part displayPart>

Now we’re going to want to look at each chord and the following chord, so we want to go from the first chord, index 0, to the second to last chord, index len(sOnlyChords) - 1, and then get each chord and the next chord. We will do that with the following sequence of commands

for i in range(0, len(sOnlyChords) - 1):
    thisChord = sOnlyChords[i]
    nextChord = sOnlyChords[i+1]
    # do something with thisChord and nextChord here

Then for each chord pair, we can create a new measure and append it to displayPart only if the first chord of each group is a triad or a seventh. For the purposes of making this example short, let’s do it only if the first chord’s root is “A”. And we can put them all in closed position.

We can create a new function to do all this and call it appendChordPairs()

def appendChordPairs(thisChord, nextChord):
    if ((thisChord.isTriad() is True or
            thisChord.isSeventh() is True) and
                thisChord.root().name == 'A'):
        closePositionThisChord = thisChord.closedPosition(forceOctave=4)
        closePositionNextChord = nextChord.closedPosition(forceOctave=4)

        m = stream.Measure()
        m.append(closePositionThisChord)
        m.append(closePositionNextChord)
        displayPart.append(m)

Okay, so I think we have this set up. Let’s replace “# do something” with appendChordPairs():

for i in range(0, len(sOnlyChords) - 1):
    thisChord = sOnlyChords[i]
    nextChord = sOnlyChords[i+1]
    appendChordPairs(thisChord, nextChord)

Do we have it? Let’s see if displayPart has anything in it?

len(displayPart)
 7

Only seven pairs of chords, well, we did limit it to chords built on A. Let’s see it!

displayPart.show()
../_images/usersGuide_10_examples1_22_0.png

Learning from the last chapter, we can label the chords with Roman Numerals in the key of A. Obviously, the first chord is always going to be “I”, but where does “I” move to? That’s more interesting.

for c in displayPart.recurse().getElementsByClass('Chord'):
    rn = roman.romanNumeralFromChord(c, key.Key('A'))
    c.addLyric(str(rn.figure))

displayPart.show()
../_images/usersGuide_10_examples1_24_0.png

Well, it’s basically everything that I expected, except for that III6 chord! I smell a modulation happening here. Let’s make all the pitches of that Chord pink so we can find them later. And we’ll softly introduce a new concept, the derivation.chain() (see Chapter 13) to make sure that everything that this note comes from is also pink.

for c in displayPart.recurse().getElementsByClass('Chord'):
    if c.lyric == 'III6':
        c.color = 'pink'
        for x in c.derivation.chain():
            x.color = 'pink'

displayPart.show()
../_images/usersGuide_10_examples1_26_0.png

Now we can find this note easily:

sChords.show()
../_images/usersGuide_10_examples1_28_0.png

And we can analyze each Measure’s key to show that indeed it is part of a modulation to f# minor:

for m in sChords.getElementsByClass('Measure'):
    k = m.analyze('key')
    print(m.number, k)
 0 E major
 1 E major
 2 A major
 3 f# minor
 4 E major
 5 A major
 6 f# minor
 7 C# major
 8 F# major
 9 b minor

This is a brief summary of some things we can do so far. I’d like to use other pieces besides this Chorale, so let’s move on to Chapter 11: Corpus Searching to learn more.